GEOG 485:
GIS Programming and Automation

Lesson 3 Practice Exercise B Solution


Below is one possible solution to Practice Exercise B with comments to explain what is going on. If you find a more efficient way to code a solution, please share it through the discussion forums.

# This script determines the percentage of cities with two park
#  and ride facilities

import arcpy
arcpy.env.overwriteOutput = True

cityBoundaries = "D:\\Data\\Geog485\\Lesson3PracticeExerciseB\\Washington.gdb\\CityBoundaries"
parkAndRide = "D:\\Data\\Geog485\\Lesson3PracticeExerciseB\\Washington.gdb\\ParkAndRide"
parkAndRideField = "HasTwoParkAndRides"
cityIDStringField = "CI_FIPS"
citiesWithTwoParkAndRides = 0
numCities = 0

# Make a feature layer of all the park and ride facilities
arcpy.MakeFeatureLayer_management(parkAndRide, "ParkAndRideLayer")

# Make an update cursor and loop through each city
with arcpy.da.UpdateCursor(cityBoundaries, (cityIDStringField, parkAndRideField)) as cityRows:
    for city in cityRows:
        # Create a query string for the current city    
        cityIDString = city[0]
        queryString = '"' + cityIDStringField + '" = ' + "'" + cityIDString + "'"

        # Make a feature layer of just the current city polygon    
        arcpy.MakeFeatureLayer_management(cityBoundaries, "CurrentCityLayer", queryString)

            # Narrow down the park and ride layer by selecting only the park and rides
            #  in the current city
            arcpy.SelectLayerByLocation_management("ParkAndRideLayer", "CONTAINED_BY", "CurrentCityLayer")

            # Count the number of park and ride facilities selected
            selectedParkAndRideCount = arcpy.GetCount_management("ParkAndRideLayer")
            numSelectedParkAndRide = int(selectedParkAndRideCount.getOutput(0))

            # If more the one park and ride found, update the row to TRUE
            if numSelectedParkAndRide >= 2:
                city[1] = "TRUE"

                # Don't forget to call UpdateRow

                # Add 1 to your tally of cities with two park and rides                
                citiesWithTwoParkAndRides += 1

            # Delete current cities layer to prepare for next run of loop
            numCities +=1

# Clean up park and ride feature layer

# Calculate and report the number of cities with two park and rides
if numCities <> 0:
    percentCitiesWithParkAndRide = ((1.0 * citiesWithTwoParkAndRides) / numCities) * 100
    print "Error with input dataset. No cities found."

print str(percentCitiesWithParkAndRide) + " percent of cities have two park and rides."

The video below offers some line-by-line commentary on the structure of the above solution: