EGEE 102
Energy Conservation and Environmental Protection

Seasonal Heating Degree Days Examples

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Example 1

Given the following set of average temperatures, by month, for State College, PA, calculate the HDD for the heating season:

Temperature per Month for State College, PA
Jan. Feb. Mar. Apr. May Jun. Jul. Aug. Sep. Oct. Nov. Dec.
25°F 28°F 37°F 48°F 59°F 67°F 71°F 70°F 62°F 51°F 41°F 31°F

Please watch the following (2:32) presentation about problem #1:

Click here for a transcript of Seasonal Heating Degree Days - Problem #1 video.

Lesson 7a, Screen 23: Seasonal Heating Degree Days

Example 3

Given the following set of average temperatures, by month, for State College, PA, calculate the HDD for the heating season:

Temperature per Month for State College, PA
Jan Feb Mar Apr May Jun July Aug Sep Oct Nov Dec
25 °F 28 °F 37 °F 48 °F 59 °F 67 °F 71 °F 70 °F 62 °F 51 °F 41 °F 31 °F

Alright, this is an interesting problem. Given the following temperatures by month for State College, we need to calculate the heating degree days for the entire season. For January, the outside temperature is 25° F. This is average temperature for 31 days in January. And February, the outside temperature is 28° F, March, 37° F and April it is 48° F and May, the temperature outside is 59° F. June, the outside temperature is 67° F, July, the outside temperature is 71° F and August it is 70° F. September, it goes on like that. September it is 62° F, and October it is 51° F, November, 41° F and December goes as 31° F.

What we need to do is basically subtract this number (25° F) from 65 so the difference is, 65 minus 25, so this is 40° F for the month of January.

( 65°25°=40° F )

The same case here (February). 65 minus 28 which happens to be 37° F.

( 65° 28°=37°F )

And if we do the same for all these months, from March through December, and then we have to multiply each month temperature difference by the number of days in the month.

So, for example, in the case of January, there are 31 days. So when you multiply 40◦ by 31 days you get 1240 degree days.

( 40° × 31 days=1240 degree days )

Similarly, we can do for all these months and add up and it turns out that for the entire year, it is 6138 degree days is for State College.

Example 2

If Ms. S. Belle moves from Birmingham, AL (HDD=2,800) to State College, PA (HDD=6,000) how much can she expect her heating bill to increase?

Please watch the following 1:34 presentation about problem #2:

Click here for a transcript of Seasonal Heating Degree Days - Problem #2 video.

Lesson 7a, Screen 24: Seasonal Heating Degree Days

Example 4

If Ms. S. Belle moves from Birmingham, AL (HDD = 2,800) to State College, PA (HDD=6,000) how much can she expect her heating bill to increase?

Alright, this is problem 1.6, if Ms. S. Belle moves from Birmingham, AL to State College, how much can she expect her heating bill to increase?

Birmingham, AL has heating degree days of 2800 and State College, PA has 6000. We need to remember this 6000 degree days. Basically what’s happening here is she is going to be heating more her home and it is increasing from 2800 to 6000. So, her increase is 6000 minus 2800 will be 3200 degree days.

( 6000  2800 = 3200 degree days ) 

And this increase (3200) is how much compared to 2800 what she has been paying for. So the increase is 3200 compared to the baseline of 2800. We need to multiply this by 100 to get the percentage. It would be an increase of 114 %.

3200 2800  × 100 = 114%

She would be spending about 114% more for her heating in State College, PA.