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What is the energy consumption of a refrigerator with a wattage rating of 700 Watts when it is operated for 24 hours a day?

**Step 1**

To solve, use the following formula:

**Energy Consumption = Power Consumption x Number of Hours Operated**

Where:

Energy Consumption= Watt/Hours (Wh) or KiloWatt/Hours (kWh)

Power Consumption= Watts (W) or kW (KiloWatts)Number of Hours Operated= Hours (h)For the example above:

Energy Consumption = 700 W x 24 h

Energy Consumption = 16800 W/h

**Step 2**

To convert from W/h to kWh/h, remember that 1kWh/h = 1000 W/h

To solve, set up as a ratio and use linear algebra to solve for ?.

$$\frac{1\text{\hspace{0.17em}}kWh}{1000\text{\hspace{0.17em}}Wh}$$ | = | $$\frac{?\text{\hspace{0.17em}}kWh}{16800\text{\hspace{0.17em}}Wh}$$ |

$$\frac{16,800\text{\hspace{0.17em}}Wh\text{\hspace{0.17em}}(1\text{\hspace{0.17em}}kWh)}{1000\text{\hspace{0.17em}}Wh}$$ | = | $$?KWh$$ |

$$16.8\text{\hspace{0.17em}}KWh$$ | = | $$?KWh$$ |

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