EGEE 102
Energy Conservation and Environmental Protection

Calculating Wall Heat Loss Example Problems

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Example #1

Please watch the following 4:58 presentation about Example #1. A house in State College, PA has 580 ft2 of windows (R = 1), 1920 ft2 of walls, and 2750 ft2 of roof (R = 22). The walls are made up of wood siding (R = 0.81), 0.75” plywood, 3” of fiberglass insulation, 1.5” of polyurethane board, and 0.5” gypsum board. Calculate the heating requirement for the house for the heating season.

Wall Heat Loss - Problem #1

Example #2

Please watch the following 9:00 presentation about Example #2. A single-story house in Anchorage, AK (HDD = 11,000) is 50 ft by 70 ft with an 8 ft high ceiling. There are six windows (R = 1) of identical size, 4 ft wide by 6 ft high. The roof is insulated to R-30. The walls consist of a layer of wood siding (R = 0.81), 2” of polyurethane board (R = 6.25 per inch), 4” of fiberglass (R = 3.70 per inch), and a layer of drywall (R = 0.45). Calculate the heat loss through the house (not counting the floor) for the season. (A good estimate for the area of the roof is 1.1 times the area of the walls, before you subtract out the area for the windows.)

Wall Heat Loss - Problem #2
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