METEO 300
Fundamentals of Atmospheric Science

5.2 What are the requirements for forming a cloud drop?

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5.2 What are the requirements for forming a cloud drop?

There are three requirements for forming a cloud drop:

  1. Moisture
  2. Aerosol
  3. Cooling

If any one of these three is missing, a cloud cannot form. We have talked about moisture and aerosol and now need to consider ways that the air can be cooled. The air needs to be cooled so that the water vapor pressure initially equals and then exceeds the saturation water vapor pressure.

An easy way to remember these key ingredients is to think of a Big MAC.

a McDonald's Big Mac`
A Big MAC. Hungry for some more?
Credit: Big Mac Snip by Ian Burt is licensed under CC BY 2.0.

Saturation occurs when e = es, w = ws, and condensation = evaporation. At saturation, RH = e/es ~ w/ws = 1, or in terms of percent, 100%. When we find the lifting condensation level (LCL) on a skew-T, we are finding the pressure level at which T (as determined from the dry adiabat) = Td (as determined from the constant water vapor mixing ratio), or when w = ws.

Two variables that are useful in discussing the cloud drop formation are the saturation ratio and the supersaturation. In Lesson 3, we introduced the saturation ratio:

S= e e s This equation is not rendering properly due to an incompatible browser. See Technical Requirements in the Orientation for a list of compatible browsers.

[5.2]

where e is the water vapor pressure and es is the saturation vapor pressure. S < 1 for a subsaturated environment, S = 1 for a saturated environment (condensation = evaporation), and S > 1 for a supersaturated environment. A second useful variable is the supersaturation:

s=S1= e e s 1 This equation is not rendering properly due to an incompatible browser. See Technical Requirements in the Orientation for a list of compatible browsers.

[5.3]

s < 0 for a subsaturated environment, s = 0 for a saturated environment, and s > 0 for a supersaturated environment. Note that s and S are both unitless.

The above equations apply only for a flat surface of pure liquid water. When we get into situations where the water has a curved surface (as in a cloud drop), contains a solute, or is in solid form, we need to think about the saturation ratio and the supersaturation relative to the equilibrium value of e, eeq, which can be different from es. So, depending on the circumstances, eeq can be es (flat liquid water), esc (curved liquid water), esol (curved solution), ei (flat ice), or some combination. We will see that a small supersaturation is actually needed to form clouds.

Check Your Understanding

The relative humidity is 85%. What is the saturation ratio? What is the supersaturation?

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ANSWER: S = 0.85 and s = 0.85 – 1 = –0.15

The relative humidity is 102%. What is the saturation ratio? What is the supersaturation?

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ANSWER: S = 1.02 and s = 0.02

Note that it is possible to have the relative humidity be greater than 100%, which makes the supersaturation positive. This condition can't last long because condensation will exceed evaporation until they become equal. But how can supersaturation happen?

Quiz 5-1: Cloud drops and liquid mass.

  1. Find Practice Quiz 5-1 in Canvas. You may complete this practice quiz as many times as you want. It is not graded, but it allows you to check your level of preparedness before taking the graded quiz.
  2. When you feel you are ready, take Quiz 5-1. You will be allowed to take this quiz only once. Good luck!